A 15 cm long human tendon was found to stretch to 3.7 mm by a force of 13.4 Newtons. The tendon was approximately round with an average diameter of 8.5mm. Calculate the elastic modulus of this tendon.

Given

Lo= 15cm

DL=3.7mm -0.37cm

r= 0.00425m

A= (pie)r^2

A=  (pie)(0.00425m)^2

A= 5.7x10^-5m^2

             1             F                          1                    13.4N

   E=  (____   ____) Lo = ( _________     __________ ) (15cm)= 

           Delta L    A                         0.37cm      5.7X10^-5m^2

   E= 9.5x10^6 N/m^2